Net Ionic Equations

[Ice-cream]

Hey can some1 help me with writing net ionic equations?

For a reaction between sulphuric acid and copper(II) carbonate, I think the equation is:

H2SO4 + CuCO3 --> H2CO3 + CuSO4

but then how do I know which one ( H2CO3 or CuSO4) breaks into ions and cancels out with the reactans to get the net ionic equation?

[YT2095]

actualy, you WILL get your CuSO4 but instead of your answer you`ll get CO2 and H2O.

not H2CO3

[Ice-cream]

ah! i see wat i done wrong. but i still have a prob. that's it's molecular/ionic equation right? so is the net ionic equation just:

Cu2+ + SO42- --> CuSO4 ?

[YT2095]

well: Cu+SO4 = CuSO4 would be more realistic as the NET equasion for copper sulphate.

 

the GROSS equasion (using your example) would be: H2SO4 + CuCO3 = CuSO4 + H2O + CO2

[Firedragon52]

Hey can some1 help me with writing net ionic equations?

For a reaction between sulphuric acid and copper(II) carbonate' date=' I think the equation is:

H2SO4 + CuCO3 --> H2CO3 + CuSO4

but then how do I know which one ( H2CO3 or CuSO4) breaks into ions and cancels out with the reactans to get the net ionic equation?[/quote']

First it helps to break the equation into ions:

2 (H+)aq + (SO4 2-)aq + (Cu 2+)aq + (CO3 2-)aq --> (H2CO3)s + (Cu 2+)aq + (SO4 2-)aq

 

If you follow the solubility rules

(http://www.csudh.edu/oliver/chemdata/solrules.htm)

you will see that carbonates are not (usually) soluble. So it forms a precipitate.

 

Then you find the spectator ions (the ions that are still in aqueous solution) and remove them from the equation like so:

2 (H+)aq + (CO3 2-)aq --> (H2CO3)s

*Let me elaborate more on spectator ions. Don't count the ions in aqueous solution to the left of the arrow that form the precipitate.*

 

and you can see that, overall, this is a combination reaction.

 

The following sites helpfully will help you more than I could:

http://www.towson.edu/~ladon/netionic.html

http://www.unco.edu/chemquest/22res27.htm

http://web.fccj.org/~ksanchez/1032/wksheet/IonicEq.html

http://www.nyu.edu/classes/tuckerman/honors.chem/lectures/lecture_13/node1.html

[Ice-cream]

i have another question...i want to write a net ionic equation for:

H2SO4(aq) + Cu(OH)2(aq) --> 2H20(l) + CuSO4(aq)

wat i think is: 2(H+) + (SO4-) + (CU2+) + 2(OH-) --> 2(H+) + 2(O-) + CuSO4 but now i have trouble cancelling out the ions ie. with the hydrogen and oxygen ions...also, is copper sulfate solid or aqueous? i thought it was aqueous but if thats the case doesnt it break down into ions and cancel out on both sides of the equation? if it is a solid then how com i'm seeing websites saying its aqueous? i am really confused!!!!!!!!

[Primarygun]

If both side do not have precipitate, ie solid, there is no net ionic equation.

[Firedragon52]

i have another question...i want to write a net ionic equation for:

H2SO4(aq) + Cu(OH)2(aq) --> 2H20(l) + CuSO4(aq)

wat i think is: 2(H+) + (SO4-) + (CU2+) + 2(OH-) --> 2(H+) + 2(O-) + CuSO4 but now i have trouble cancelling out the ions ie. with the hydrogen and oxygen ions...also' date=' is copper sulfate solid or aqueous? i thought it was aqueous but if thats the case doesnt it break down into ions and cancel out on both sides of the equation? if it is a solid then how com i'm seeing websites saying its aqueous? i am really confused!!!!!!!![/quote']

Be careful here. On the right side of you equation you have a product in liquid phase [2H20(l)]. Only products in aqueous solution are ionized. So the Molecular Ionic Equation would be:

2(H+)aq + (SO4 2-)aq + (Cu2+)aq + 2(OH-)aq --> 2H20(l) + (Cu2+)aq + (SO4 2-)aq

So from here, hopefully you can find the spectator ions on your own.

[RecycleMexic]

Dear Friends

 

I have this equation

Cu(metal wire) + H2SO4(aq 1M) ------> CuSO4(aq 1 M) + H2 (g)

 

With this equation at the moment of add the cooper and the sulfuric acid the reaction is static and does not produce the CuSO4(qa), someone can help me....

[RyanJ]

Dear Friends

 

I have this equation

Cu(metal wire) + H2SO4(aq 1M) ------> CuSO4(aq 1 M) + H2 (g)

 

With this equation at the moment of add the cooper and the sulfuric acid the reaction is static and does not produce the CuSO4(qa)' date=' someone can help me....[/quote']

 

You'll probably need concentrated Sulphuric acid or maybe heated acid would do the trick, copper is quite unreactive and so needs some "encouragement" to make it react

 

Cheers,

 

Ryan Jones

[jdurg]

First it helps to break the equation into ions:

2 (H+)aq + (SO4 2-)aq + (Cu 2+)aq + (CO3 2-)aq --> (H2CO3)s + (Cu 2+)aq + (SO4 2-)aq

 

If you follow the solubility rules

(http://www.csudh.edu/oliver/chemdata/solrules.htm)

you will see that carbonates are not (usually) soluble. So it forms a precipitate.

 

Then you find the spectator ions (the ions that are still in aqueous solution) and remove them from the equation like so:

2 (H+)aq + (CO3 2-)aq --> (H2CO3)s

*Let me elaborate more on spectator ions. Don't count the ions in aqueous solution to the left of the arrow that form the precipitate.*

 

and you can see that' date=' overall, this is a combination reaction.

 

The following sites helpfully will help you more than I could:

http://www.towson.edu/~ladon/netionic.html

http://www.unco.edu/chemquest/22res27.htm

http://web.fccj.org/~ksanchez/1032/wksheet/IonicEq.html

http://www.nyu.edu/classes/tuckerman/honors.chem/lectures/lecture_13/node1.html[/quote']

 

You do realize that H2CO3 is most DEFINITELY not a solid, correct? Actually, I believe that copper carbonate is a solid material. So in this case, the proper net ionic equation would be:

 

2H+(aq) + CuCO3(s) => Cu+2(aq) + H2O(l) + CO2(g)