hkus10 Posted March 26, 2011 Posted March 26, 2011 Suppose that the solution set to a linear system Ax = b is a plane in R^n with vector equation x = p + su + tv , s, t ∈ R . Prove that p is a solution to the nonhomogeneous system Ax = b , and that u and v are both solutions to the homogeneous system Ax = 0 . (Hint Try choices of s and t). Should I start from A(p + su + tv) = b? If yes, what should I do from here? If no, where should I start?
timo Posted March 26, 2011 Posted March 26, 2011 The first part is more trivial than you probably expect it. For the 2nd part of the question (Au=0 and Av=0), your start is indeed promising. Keep in mind what "linear" means for that one.
hkus10 Posted March 27, 2011 Author Posted March 27, 2011 Ap + A(su) + A(tv) = b Ap + s(Au) + t(Av) = b Ap + s(0) + t(0) = b Ap = b Is this correct?
DrRocket Posted March 28, 2011 Posted March 28, 2011 Ap + A(su) + A(tv) = b Ap + s(Au) + t(Av) = b Ap + s(0) + t(0) = b Ap = b Is this correct? You shoulde be able to determine for yourself when you have a valid proof for a given proposition. But,, no, this is not a valid proof for the proposition that you stated. Your statements in fact assume the conclusion of the proposition.
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