question Posted October 2, 2004 Share Posted October 2, 2004 the protocol: Vg = volume not accessable to solvent (volume of the gel matrix) Vg cannot be measured directly. However, it should apparant that: Vg = Vt - volume accessable to solvent We can measure the volume accessable to the solvent, using a small molecule such as acetone which can be easily visualized by a UV detector. example: Pharmacia Superose 6 column - volume accessable to solvent = 19.5 mL (measured with acetone) Vg = Vt - 19.5 mL = 24.4 - 19.5 mL = 4.9 mL --------------------------------------------------------------------------------------- hi guys! i just find this calculation very unreasonable, since as we know Vt=Vi+Vg+Vo, where Vt =total column volum, Vo= void volum due to EXTREMELY huge substances, Vg= volum of matrix and Vi=volum inside the beads due to EXTREMELY small substances. my question is, how come we use acetone (small molecule) to determine both Vo and Vi, since Vg= Vt- (Vo+Vi)? hopes for replies! thanks! Link to comment Share on other sites More sharing options...
question Posted October 2, 2004 Author Share Posted October 2, 2004 by the way here is the link; http://itsa.ucsf.edu/%7Ehdeacon/Stokesradius.html Link to comment Share on other sites More sharing options...
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