ERTW Posted April 17, 2011 Posted April 17, 2011 (edited) you want to take the derivative of that function? if that is what you want, its simple power rule: [math] \frac{df(x)}{dx} = (-3)(-8)x^{-8-1} + 2\frac{1}{2}x^{1/2-1} [/math] you get: [math] \frac{df(x)}{dx} = \frac{24}{x^9} + \frac{1}{\sqrt{x}} [/math] Edited April 17, 2011 by ERTW
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