Triston Posted June 4, 2011 Posted June 4, 2011 For silver chloride in water Ksp = 1.8 x 10-10. How many moles of silver chloride can be dissolved in 1.0 L of water? If the solubility of CuBr in water is 2.0 x 10-4 mol/L, what is the Ksp of CuBr? I cant even figure out how to start on this. It is not in my textbook, it's not in lecture notes, its not on google. So i havent been able to attempt much. If someone could point me in the right direction or even show me how to do an example i would be greatful. Thanks
mississippichem Posted June 4, 2011 Posted June 4, 2011 Alright, for the first question lets consider the balanced reaction: [ce] AgCl_{(s)} \rightleftarrows Ag^{+}_{(aq)} + Cl^{-}_{(aq)} [/ce] so, [math] K_{sp} [/math] is given by: [math] K_{sp} = \frac{[Ag^{+}][Cl^{-}]}{[AgCl]} [/math] The activity of the solid [ce]AgCl[/ce] is so close to unity that we can neglect it so we have: [math] K_{sp} = [Ag^{+}][Cl^{-}] [/math] I've brought you very close to an answer on the first question, now just remember that these concentration come in units of [math]mol \cdot L^{-1} [/math]. Try this one out, then get back to me about the second question.
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now