Triston Posted June 4, 2011 Share Posted June 4, 2011 For silver chloride in water Ksp = 1.8 x 10-10. How many moles of silver chloride can be dissolved in 1.0 L of water? If the solubility of CuBr in water is 2.0 x 10-4 mol/L, what is the Ksp of CuBr? I cant even figure out how to start on this. It is not in my textbook, it's not in lecture notes, its not on google. So i havent been able to attempt much. If someone could point me in the right direction or even show me how to do an example i would be greatful. Thanks Link to comment Share on other sites More sharing options...
mississippichem Posted June 4, 2011 Share Posted June 4, 2011 Alright, for the first question lets consider the balanced reaction: [ce] AgCl_{(s)} \rightleftarrows Ag^{+}_{(aq)} + Cl^{-}_{(aq)} [/ce] so, [math] K_{sp} [/math] is given by: [math] K_{sp} = \frac{[Ag^{+}][Cl^{-}]}{[AgCl]} [/math] The activity of the solid [ce]AgCl[/ce] is so close to unity that we can neglect it so we have: [math] K_{sp} = [Ag^{+}][Cl^{-}] [/math] I've brought you very close to an answer on the first question, now just remember that these concentration come in units of [math]mol \cdot L^{-1} [/math]. Try this one out, then get back to me about the second question. Link to comment Share on other sites More sharing options...
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