thickness of copper deposited on cathode(aluminum)

[wan]

People,

now i'm doing research project on aluminium..so i need do the electrolysis to coating my sample (aluminum)..the electrolysis is using copper(II) sulphate solution, copper pipe (anode) and my sample aluminium (cathode).so now,i want to know how to know and calculate the thickness of copper deposited on my sample..if say..i use the 0.6A DC electrical current in 2 hours..so how to calculate the thickness..or use the faraday's formula... (can someone explain,because i totally confuse and blur)thank you

Edited June 14, 2011 by wan

[Yoseph]

If the copper is deposited evenly you can just do (width after electrolysis - width before electrolysis) / 2? "Width" being the width of the cross section of the cathode... Or am I missing something? If it's not distributed evenly then I think it might be better to weigh the cathode before and after the electrolysis and compare the weights. By doing that you could even guess how many atoms of copper were deposited as we know the atomic mass of copper and aluminium from the periodic table. You would need to use fairly pure water though.