Treadstone Posted October 12, 2004 Share Posted October 12, 2004 anyone know the syntax for soloving a systems of eqs? I forgot what is was and cant re-figure it out...i know its somethng like solve(f(x,y)=a; or , f(x,y)=b, or ; (a,b)) or smoething like that for example a + b = 2 3a + b^2 = 8 just pull out of my head for the syntax purposes Link to comment Share on other sites More sharing options...
Dave Posted October 12, 2004 Share Posted October 12, 2004 It won't do it for you; you have to re-arrange in terms of one variable using Solve() and then use | to pipe it into the other formula. Link to comment Share on other sites More sharing options...
Treadstone Posted October 12, 2004 Author Share Posted October 12, 2004 are you sure? becuase i distinctly remember doing it in calc last year...but ya i saw the | in the manual i also have another, but unrelated, question....how do you find the maximum of a function say, y(t)=2sin(3t) + cos(3t) Link to comment Share on other sites More sharing options...
Dave Posted October 12, 2004 Share Posted October 12, 2004 Differentiate it and set the differential equal to zero to find stationary points, then look at the second derivative to determine whether your stationary point is a maxima or a minima. Link to comment Share on other sites More sharing options...
Treadstone Posted October 12, 2004 Author Share Posted October 12, 2004 ahhh, thank you Link to comment Share on other sites More sharing options...
Dave Posted October 12, 2004 Share Posted October 12, 2004 No problem Link to comment Share on other sites More sharing options...
Treadstone Posted October 13, 2004 Author Share Posted October 13, 2004 i figured out the syntax... solve(2x+3y=5 and x-y=3,{x,y}) that will solve both for x and y....just had to ask my calc proff from last year. Link to comment Share on other sites More sharing options...
MadScientist Posted October 13, 2004 Share Posted October 13, 2004 I don't know if this is of any use: http://www.rit.edu/~jmwsma/calculators/ti92/ti92links/ti92links.html Link to comment Share on other sites More sharing options...
Dave Posted October 13, 2004 Share Posted October 13, 2004 i figured out the syntax... solve(2x+3y=5 and x-y=3' date='{x,y}) that will solve both for x and y....just had to ask my calc proff from last year.[/quote'] Works on my TI-89 as well Link to comment Share on other sites More sharing options...
Treadstone Posted October 13, 2004 Author Share Posted October 13, 2004 its wicked helpful, lol Link to comment Share on other sites More sharing options...
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