raid517 Posted July 20, 2011 Share Posted July 20, 2011 Please can someone show me the steps needed to go about rearranging the equation Eph = hc/lambda to make lambda (the wavelength of the light) the subject? I'm totally stuck and I have an exam in the morning, I know it should be simple but I'm just not getting it. Any and all help is appreciated. Link to comment Share on other sites More sharing options...
imatfaal Posted July 20, 2011 Share Posted July 20, 2011 Multiply both sides by wavelength (and cancel out any term over itself) divide both sides by energy (and then cancel out again) Link to comment Share on other sites More sharing options...
khaled Posted July 24, 2011 Share Posted July 24, 2011 (edited) [math]Eph = \frac{hc}{\lambda}[/math] [math]\frac{Eph \lambda}{Eph} = \frac{hc \lambda}{Eph \lambda}[/math] [math]\lambda = \frac{hc}{Eph}[/math] Edited July 24, 2011 by khaled Link to comment Share on other sites More sharing options...
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