wanabe Posted July 30, 2011 Share Posted July 30, 2011 I'm thinking about making a new type of hot air balloon, but I need to see if I can even make the math/physics work out let alone the engineering. I would be more than happy to collaborate on the effort, may be make some one very rich. How much heat would it take to lift a spherical hot air balloon (r= 81.4) x ft in to the air? How much heat at x altitude (function would be appreciated) would be needed to raise the balloon 200 ft? I'm most concerned with the lift off, as once in flight I have a different source of power than a flame. Link to comment Share on other sites More sharing options...
swansont Posted July 30, 2011 Share Posted July 30, 2011 PV = nRT for an ideal gas, which should be a good enough approximation If the inflated volume is constant and the pressure is constant, then the density varies inversely with temperature (one must use an absolute temperature here, e.g. Kelvins) The buoyancy force is the weight of the displaced air. 1 mole of an ideal gas displaces 22.4L at STP, which is about 29 grams of mass. If you doubled the temperature from 273K to 546K (i.e. 273 ºC), the air density inside the balloon drops in half, and you could lift 14.5 grams I'm using 0º C and 1 atmosphere as STP here, which is apparently now an "old" definition according to IUPAC, but it's what I grew up on http://en.wikipedia.org/wiki/Standard_conditions_for_temperature_and_pressure Link to comment Share on other sites More sharing options...
alpha2cen Posted July 30, 2011 Share Posted July 30, 2011 This is an approximate value. First, we set up a force balance equation about the balloon. We consider air as an ideal gas. Vballoon Loballoon air + mload +mballoon mass= Vballoon Loair(h) Vballoon{(MairP(h) ) /(R Tballoon) }+ mload +mballoon mass= Vballoon Loair(h) So Tballoon={ Vballoon Mair P(h)} / {R (Vballoon Loair(h) -mload -mballon mass) } The required heat energy is like this. Q =~ Vballon Loair (h) Cp air(Tballoon - Tair) + Qloss At the steady state Q/t = Qloss/t The required energy from the beginning is Q =~ Vballon Loair (h) Cp air(Tballoon - Tair) + Qloss/t ttravel Link to comment Share on other sites More sharing options...
TonyMcC Posted July 30, 2011 Share Posted July 30, 2011 Just a couple of practical points.You do not make clear the units of measurement. Is the balloon 81.4 ft radius or 81.4 something else to be raised X feet into the air? You also need to know the total weight of all you need to lift. This includes the balloon envelope, air heating mechanism, pilot and whatever is going to provide the source of power that you mention once your machine is in the air. Hot air balloons are pretty big structures which generally carry quite light loads. If you are going to force it through the air you will need a powerful motor which will surely be heavy. Link to comment Share on other sites More sharing options...
wanabe Posted August 1, 2011 Author Share Posted August 1, 2011 (edited) Ah yes: pv=nrt, fond memories. (The units are ft sorry) The dimensions I used are based on a spherical version of a 3-5 passenger hot air balloon. The "power" source I'm planning to use weighs about 90lbs. Let's assume 150lbs is the weight of a "passenger". The "power" source can deliver 10% of the "average homes" "power". My hope is to carry at least 2 people and their cargo. Is this enough information? If so is this feasible? Edited August 1, 2011 by wanabe Link to comment Share on other sites More sharing options...
TonyMcC Posted August 1, 2011 Share Posted August 1, 2011 (edited) Ah yes: pv=nrt, fond memories. (The units are ft sorry) The dimensions I used are based on a spherical version of a 3-5 passenger hot air balloon. The "power" source I'm planning to use weighs about 90lbs. Let's assume 150lbs is the weight of a "passenger". The "power" source can deliver 10% of the "average homes" "power". My hope is to carry at least 2 people and their cargo. Is this enough information? If so is this feasible? I'm not really into maths and anyway you will need to vary the heat required according to weather and load conditions. However this link makes clear you will need at the very least 2MW (possibly as much as 12MW). http://en.wikipedia.org/wiki/Hot_air_balloon Edited August 1, 2011 by TonyMcC Link to comment Share on other sites More sharing options...
wanabe Posted August 29, 2011 Author Share Posted August 29, 2011 So unless my generator can create this power range 2-12MW, this thing can't get off the ground, am I correct? Link to comment Share on other sites More sharing options...
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