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Posted

How do you solve equations like this??

 

-0.5lnx= x^2

 

the only way i cant think of is expanding lnx as a series and get an approximate answer, but that is as good as it gets. Can anyone help me please??

thank you

Posted

[math]- 1/2 ln(x) = x^2[/math]

 

[math]ln(x) = - 2 x^2[/math]

 

You need to use Lambert W Function, as Shadow said .. regarding your equation have complex roots,

 

here is the solution from Wolfram|Alpha

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