Using Scilab ODE solver

[Runninfarmer]

This might be a dumb question but when solving ODE's with scilab and you set the independent variable points at which you want to evaluate, what is the middle number used for in t = 0:0.1:5 for the example:

 

function dx = f ( t , x )

dx = sin (2 t ) ;

endfunction

 

t0 = 0

x0= -0.5

t=0:0.1:5;

x = ode(x0, t0, t, f);

plot2d(t, x)

 

Here's the link for the example: http://scilab.in/files/workshops/15-04-2010-mumbai/sengupta-ode.pdf

 

 

Thanks for the help!

[Bignose]

looks like a step size to me. That is you step t from 0 to 5 in 0.1 increments: 0.0, 0.1, 0.2, .... 4.8, 4.9. 5.0.

[baxtrom]

This might be a dumb question but when solving ODE's with scilab and you set the independent variable points at which you want to evaluate, what is the middle number used for in t = 0:0.1:5 for the example:

 

Like in Matlab, that command will create a vector t with values from zero to 5 with stepsize 0.1, i.e.

 

t = [0, 0.1, 0.2, 0.3, .... 4.8, 4.9, 5.0].