biochem gibs free energy

[tedc]

Hi:

 

For the reaction:

 

Fructose 1,6-bisphosphate (F-1,6-BP) ↔ DHAP + GAP

 

The standard free energy change, ΔG°', is -23.8 kJ/mol

 

Suppose that in a mammalian liver cell at 37 °C (310 K), the actual metabolite concentrations are as follows:

 

[F-1,6-BP] = 1.4 x 10^–5 M

 

[DHAP] = 1.6 x 10^–5 M

 

[GAP] = 3 x 10^–6 M

 

Calculate the actual free energy change (ΔG) at 37 °C (310K).

 

Question options:-56.2 kJ/mol

 

 

-23.8 kJ/mol

 

-8.6 kJ/mol

 

-3.2 X 10⁴ kJ/mol

 

 

 

I chose -56.2 and repeated all the calculations several times, but it doesnt seem to be the right answer, please let me know any mistakes thanks.

-23.8+0.00831(310)ln((1.6x10^-5x3x10^-6)/(1.4x10^-5))=-56.2