quick question(s)

[sysD]

hiya.

ok, so i've got an assignment that's due around 9AM EST on the 13th of Sept (this morning).

If anyone could help me out before then, I'd be forever grateful =p

 

 

 

 

Here's the first question:

 

Solve for "x"

2x^3 + 6x^2 -x = 3

 

and so far, i have:

 

(x+3)(2x^2-1)=0

 

Its a four mark question, so I have to be missing something here.

 

 

The other question is:

When (ax^3 - 4x^2 +5x -3) is divided by (x+2) and (x-1), the remainders are equal. Find "a"

How would I go about doing this?

[ecoli]

For #1 - try setting both parts (in paranthesis) equal to zero and solve for x. Sometimes, there's more than 1 value of x which satisfies an equation.

[rktpro]

For #1 - try setting both parts (in paranthesis) equal to zero and solve for x. Sometimes, there's more than 1 value of x which satisfies an equation.

 

That sometimes is found by the degree of polynomial.