logearav Posted October 3, 2011 Share Posted October 3, 2011 Revered members, Kindly see my attachment. i) vcosθ in a direction parallel to OY. (ii) vsinθ in the direction perpendicular to OY. The component vsinθ has no effect along vertical diameter YOY' since it is perpendicular to OY. Revered members, why the perpendicularity of vsinθ to OY makes no effect along vertical diameter? Link to comment Share on other sites More sharing options...
logearav Posted October 13, 2011 Author Share Posted October 13, 2011 Why none has answered my question? Link to comment Share on other sites More sharing options...
swansont Posted October 13, 2011 Share Posted October 13, 2011 I 'm not sure I understand the question. The topic is SHM, but you seem to be asking a basic question about math and forces. A force in the x direction cannot affect motion in the y direction, because they are perpendicular. There is no work done because the dot product between force and displacement would be zero. Since that has nothing inherently to do with SHM, I don't know if that's what you are looking for. 1 Link to comment Share on other sites More sharing options...
logearav Posted October 13, 2011 Author Share Posted October 13, 2011 Thanks a lot for the reply. Let me explain, the particle P is moving along the circumference of the circle. Now the velocity of the particle can be resolved into two components vsin and vcos. Since vsin is perpendicular to the vertical diameter, it has no effect on vertical diameter. My question is why the perpendicularity of vsin to OY(vertical diameter) results in no effect on OY. Hope i clarified. Thanks again for your effort in answering my query Link to comment Share on other sites More sharing options...
swansont Posted October 13, 2011 Share Posted October 13, 2011 It's by definition. A big reason we use orthogonal coordinate systems. Link to comment Share on other sites More sharing options...
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