triclino Posted October 14, 2011 Posted October 14, 2011 (edited) Prove that (0,2) is open in [math](R^2,d)[/math] where d is the discrete metric: .....................................................d(x,y) = 0 ,if x=y........................................................... ......................................................d(x,y) =1 ,if [math]x\neq y[/math]..................................... Obviously we have to prove that: for all xe(0,2) ,there exists ε>0 such that B(x,ε) is a subset of (0,2) ,or for all xε(0,2) ,there exists ε>ο such that yεB(x,y) iplies [math]0<y_{1}<2[/math],where x =[math](x_{1},0)[/math] and y=[math](y_{1},y_{2})[/math] AM I correct?? Edited October 14, 2011 by triclino
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