Sharky Posted October 16, 2011 Posted October 16, 2011 Hello, I am currently working out the chemical equations to prepare ReCl3 solutions in order to synthesis NaYF4. The following equation is used to prepare the chloride solution: Re2O3 + 6 HCl = 2 ReCl3 + 3 H2O In order to prepare 0.5 mol/L of ReCl3 solution, I divided the equation by 4, then I will add more water to the solution to achieve the required concentration. Going forward with the procedure, I should achieve NaYF4. My question is if I want to synthesis NaYF4:20%Er (this means 80% NaYF4 and 20%NaErF4), should the proportion of metal oxides be 80% Y2O3 and 20% Er2O3? Please help me!
John Cuthber Posted October 16, 2011 Posted October 16, 2011 Why is your post full of stuff about rhenium?
Sharky Posted October 16, 2011 Author Posted October 16, 2011 There isn't any rhenium at all..."Re" stands for "Rare Earth" So have you got any idea about the ratio of metal oxides?
John Cuthber Posted October 17, 2011 Posted October 17, 2011 I checked with IUPAC, Re really does stand for rhenium. http://www.iupac.org/ There's a vague convention about using Ln as a symbol for a general lanthanide. There's also a trend away from calling them rare earths because they are not earths and they are not (generally) all that rare. The question isn't really clear. They may mean 20% m/m or possibly 20% mol/mol. I guess the two ways to find out are to ask the people to whom you are referring, or to try the experiment.
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