evangela7 Posted December 22, 2011 Posted December 22, 2011 I do not understand why I am getting this problem wrong on my homework. Rank the compounds in the following group in order of decreasing rate of solvolysis in aqueous acetone. a) 2-methyl-4-chloro-butane b) 2-methyl-3-chloro-butane c) 2-methyl-2-chloro-butane I know acetone is polar aprotic so it favors Sn2 reactions. Therefore, wouldn't it be in the following order: primary > secondary > tertiary or a>b>c? Please correct me if I'm wrong...
hypervalent_iodine Posted December 22, 2011 Posted December 22, 2011 Looks good to me. Although it should be noted that the tertiary alkyl halide won't undergo SN2.
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