Tracker Posted January 9, 2012 Posted January 9, 2012 (edited) X is a n*k matrix, k < n X is of full rank k (full column rank) X'X is of full rank and therefore invertible [math] P_x = X(X'X)^{-1}X'[/math] Show that [math]P_x[/math] is symmetric and idempotent. I figured out how to show it is idempotent. Here is my attempt to show it is symmetric: [math] (P_x)' = (X(X'X)^{-1}X')' = X'[(X'X)^{-1}]'X = X'(XX')^{-1}X[/math] Maybe someone has a sheet for all the algebra rules for linear algebra that would be helpful? Edited January 9, 2012 by Tracker
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now