Tracker Posted January 9, 2012 Share Posted January 9, 2012 (edited) X is a n*k matrix, k < n X is of full rank k (full column rank) X'X is of full rank and therefore invertible [math] P_x = X(X'X)^{-1}X'[/math] Show that [math]P_x[/math] is symmetric and idempotent. I figured out how to show it is idempotent. Here is my attempt to show it is symmetric: [math] (P_x)' = (X(X'X)^{-1}X')' = X'[(X'X)^{-1}]'X = X'(XX')^{-1}X[/math] Maybe someone has a sheet for all the algebra rules for linear algebra that would be helpful? Edited January 9, 2012 by Tracker Link to comment Share on other sites More sharing options...
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