Primarygun Posted November 7, 2004 Posted November 7, 2004 Why does aluminium so readily form an oxide layer on its surface compared with other metals? What does Iron(II , III) means? Fe3O4 II= FeO III=Fe2O3 I recognised that it is the sum of the two oxides, but shouldn't it be the mean of the two oxides? Also, is the reaction of potassium reaction a displacement reaction?
budullewraagh Posted November 7, 2004 Posted November 7, 2004 aluminum is quite an active metal. if you look at the alkali metals, they do the same thing too because oxygen is very electronegative and aluminum has a low ionization energy
jdurg Posted November 7, 2004 Posted November 7, 2004 And with the alkali metals, the metal oxide is soluble in water and isn't strongly bound to the metal. Therefore, it will expose more of the metal to reaction. While aluminum is pretty darned reactive, the oxide is NOT soluble in water and it adheres to the metal very strongly, thus protecting it from further reaction.
budullewraagh Posted November 8, 2004 Posted November 8, 2004 well, the alkali oxides becomes the hydroxides in water, do they not?
Primarygun Posted November 8, 2004 Author Posted November 8, 2004 In fact, what's a displacement reaction? It is mainly occured in a solution?
mak10 Posted November 8, 2004 Posted November 8, 2004 displacement reactions are those where a particular molecule/element in a compound gets displaced by a more reactive molecule/element in that compound, by a reaction. Like when chlorine displaces iodine from KI and forms KCl in a reaction.... since it is more electronegative and thus reactive than iodine. It can occur in solutions as well as in gaseous reactions... i think. -mak10
budullewraagh Posted November 9, 2004 Posted November 9, 2004 speaking of potassium iodide, a better way than using chlorine is to use a powerful oxidizing agent like hydrogen peroxide
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