Mental Math Posted February 5, 2012 Posted February 5, 2012 Let’s have a game. For this trick, secretly write 73 on a piece of paper, fold it up, and give to an unsuspecting friend. Now have your friend select a four-digit number whatever (say, 3125) and enter it twice into a calculator. (31253125) Announce that the number is divisible by 137 and have him verify it on his calculator. Next, announce that he can now divide by his original four-digit number. After he has done so, dramatically command him to look at your prediction on the paper. It will match his calculator display: 73! Want to know the simple math behind this "TRICK"?
John Cuthber Posted February 5, 2012 Posted February 5, 2012 I tried calculating 73! but it's too big for my calculator. I think you could do the same trick in binary, but you need to get them to choose 5 digit numbers and the corresponding "magic" numbers are 11 and 1011.
TonyMcC Posted February 5, 2012 Posted February 5, 2012 (edited) The secret lies in the fact that if you divide the 8 digit number by the 4 digit number you always get 10001. If you divide this by 137 you always get 73. This gives the the 8 digit number 137 as one of its factors.( 8digit number = 4digit number * 137* 73 ) Used spoiler because OP seems to ask if we can work out what he knows. Edited February 5, 2012 by TonyMcC
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