Guest deenhead Posted November 11, 2004 Posted November 11, 2004 A question was posed in our calc class about how the general formula for the taylor series expansion of arcsin was created. Here is the general formula: I tried calculating each derivative. But after the fifth one, it got too long and I still couldn't see a pattern. Here is a readout from the ti-89 f (0) = 0 f` (0) = 1 f`` (0) = 0 f```(0) = 1 f^4 (0) = 0 f^5 (0) = 9 f^6 (0) = 0 f^7 (0) = 225 = 15^2 f^8 (0) = 0 f^9 (0) = 105^2 ? So I was wondering if any of you could help me in trying to find how the general formula was created. thanks
MandrakeRoot Posted November 12, 2004 Posted November 12, 2004 Let me help you a bit : The general form of the n-th derivative of the arcsine function has the following form [math]\frac{\partial f^{(n)}}{\partial x^n}(x) = (1 - x^2)^{-\frac{2n-1}{2}}p_n(x)[/math], where p_n is a polynomial that satisfies the following [math]p_{n+1}(x) = (2n-1)xp_n(x) + (1- x^2)p_n'(x)[/math], Here n >= 1 and p_1 is all constant 1 function. Mandrake
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