blazinfury Posted April 26, 2012 Posted April 26, 2012 I have a question about Ksp and L'Chateliur's Principle. Lets says we have the following: NaCl(s) ----> Na+(aq) + Cl-(aq) If we add more NaCl(s), the equilibrium does now shift since (s) and (l) do not affect Keq. In addition, the reaction does not shift either b/c L'Chateliur's Principle shifts are not affected by (s) or (l). But what about Q. Q is the [P]/[R] at any time. If we add more solid, don't we in fact increase the value of Q. If so, can't we then compare Q and K to see which way the reaction shifts and/or if we can still dissolve more solid? Thanks.
CaptainPanic Posted April 26, 2012 Posted April 26, 2012 What is Q? What is R? What is P? Not everybody is still in school, and not everybody uses the same books as you. Also, did you maybe mean "Le Chatelier's Principle"? The quality of the answer is often determined by the quality of the question. Especially since you copy-pasted the exact same question onto another website too, you might as well spend a little more time to remove the mistakes. Sorry that I cannot help you, but I really don't understand your question.
blazinfury Posted April 26, 2012 Author Posted April 26, 2012 I am sorry if I was not clear enough. P- product R- reactant Q- Quotient or in some cases IP (ionization product)
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