kris091 Posted April 28, 2012 Posted April 28, 2012 hey guys what is the entropy change in an adiabatic reversible process. i thought its 0 as U=W+Q and for an adiabatic process Q and W are 0. thanks guys
juanrga Posted April 28, 2012 Posted April 28, 2012 hey guys what is the entropy change in an adiabatic reversible process. i thought its 0 as U=W+Q and for an adiabatic process Q and W are 0. thanks guys For a closed system and reversible process TdS=dQ. Adiabatic process means dQ=0. Therefore dS = 0
kris091 Posted April 28, 2012 Author Posted April 28, 2012 For a closed system and reversible process TdS=dQ. Adiabatic process means dQ=0. Therefore dS = 0 ohhh ok bro, thanks a lot that was really helpful
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