Boolean Algerba Problem

[ahmedzica]

Hello Guys,

 

I wanna know how i could simpify this expression . It's been 5 days since I started thinking about it

 

so how can i simplify that expression

 

A'B'C' + A'B'C + A'BC' + AB'C' to equal A'B' + A'C+ B'C'

 

 

 

Thanks alot,

 

Ahmed.

[mathematic]

The expression doesn't look right. The first two terms add up to A'B', but the rest looks wrong, since C has no role.

[phillip1882]

A'B'C' + A'B'C + A'BC' + AB'C'

 

A'B'(C' +C) +A'BC' +AB'C'

A'B' +C'(A'B +AB')

A'B' +C'

so yeah there's something wrong with the way you have the equation.

[mathematic]

A'B'C' + A'B'C + A'BC' + AB'C'

 

A'B'(C' +C) +A'BC' +AB'C'

A'B' +C'(A'B +AB')

A'B' +C'

so yeah there's something wrong with the way you have the equation.

 

A'B + AB' is not everything. However your point is correct.

[ZeroZero]

here is a site that might interest you. i found it very useful well written and have studied the course

 

 

 

http://www.allaboutcircuits.com/vol_4/chpt_7/5.html

[phillip1882]

whoops. hehe, i was thinking that '(A'B) <=> (AB')

which of course it is not.

 

 

 

[khaled]

whoops. hehe, i was thinking that '(A'B) <=> (AB')

which of course it is not.

 

(a' AND b)' <=> a OR b' --de Morgan Law

[Arun Nayak]

Boolean algebra is a very interesting thing...but the question you are giving is i think wrong one..to get the best result u may take the help of exports form internet...