GunnerVIII Posted March 11, 2003 Posted March 11, 2003 When I did this question I got an answer that seemed a little off. Im not sure if I did something wrong or this was infact the correct answer, anyway the question was: A rifle can fire a bullet at 1000ms-1. If it is fired vertically into the air, what is the maximum height reached? For how long is it in the air? I worked out that, u=1000ms-1 v=0 a=-9.8ms-2 t=? s=? I worked out the time first using v=u+at 0=1000-9.8.t and I got 102 sec I then worked out the maximum height reached using s=ut+1/2at^2 s=1000.102+1/2.-9.8.102 and I got 51,021 m Did anyone else get the same answer or have I done something wrong? Thanks
greg1917 Posted March 11, 2003 Posted March 11, 2003 yeah. different ways to do it. since v^2 = u^2 + 2as you can rearrange to give s = (v^2 - u^2) / 2a which gives 51020m which is close enough to ure figure. and yeah v = u + at which gives t as 102s.
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