igor namus Posted August 24, 2012 Posted August 24, 2012 Does it matter if a bosun meets an anti-bosun?
Curious hassan Posted September 14, 2012 Posted September 14, 2012 1345769944[/url]' post='698651']Does it matter if a bosun meets an anti-bosun? Of all the 'regular' bosons only the W boson has an 'anti-particle. The W- and W+ are anti-particles. The rest, like the photon, are their own anti-Particle.W bosons can decay to a lepton and neutrino or to an up-type quark and a down-type quark. The decay width of the W boson to aquark–antiquark pair is proportional to the corresponding squared CKM matrix element and the number of quark colours, NC = 3. The decay widths for the W bosons are then proportional to:LeptonsUp quarksCharm quarkse+ν e1ud3|Vud|2cd3|Vcd|2μ+ν μ1us3|Vus|2cs3|Vcs|2τ+ν τ1ub3|Vub|2cb3|Vcb|2Here, e+, μ+, τ+ denote the three flavours of leptons (more exactly, the positive charged antileptons). ν e, νμ, ντ denote the three flavoursof neutrinos. The other particles, starting with u and d, all denote quarks and antiquarks (factor NC is applied). The various Vij denote the corresponding CKM matrix coefficients. Unitarity of the CKM matrix implies that |Vud|2 + |Vus|2 + |Vub|2 = |Vcd|2 + |Vcs|2 + |Vcb|2 = 1. Therefore the leptonic branching ratios of the W boson are approximately B(e+ν e) = B(μ+νμ) = B(τ+ντ) = 1⁄9. The hadronic branching ratio is dominated by the CKM-favored udand cs final states. The sum of the hadronic branching ratios has been measured experimentally to be 67.60±0.27%, withB(l+νl) = 10.80±0.09%.[9] [edit]
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