tjpj77 Posted September 5, 2012 Posted September 5, 2012 (edited) Calculate the amount of glycine and HCl required to prepare a 1L solution of 0.1M buffer at a pH of 2.0. The pKa of the glycine carboxyl group is 2.4 and the pKa of the amine group is 9.6. The amu of glycine is 75. Using pH = pKa + log ([A-]/[HA]), I get 2.0 = 6.0 + log ([A-]/[HA]). I get 6.0 because that is the average of the pKa values of glycine. But we can't have the log of a negative number, so I'm totally stuck here... Thanks... Edited September 5, 2012 by tjpj77
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