Semjase Posted September 13, 2012 Posted September 13, 2012 The Semjase equation for pi ln(.5-.75^.5)= -a+i*pi Anyone care to prove or disprove?
mathematic Posted September 13, 2012 Posted September 13, 2012 (edited) π = -2iln(i) so what! Edited September 13, 2012 by mathematic
Bignose Posted September 14, 2012 Posted September 14, 2012 (edited) This really isn't anything too profound. The extension of the natural logarithm to the negative numbers is commonly expressed as [math]Log(z) = \ln® + i\theta[/math] where [math]z=r\exp(i\theta)[/math]. For a real negative number, [math]\theta = -\pi[/math]. So, all you did was shove a fairly weird negative number in there. To be exceptionally pedantic, the natural logarithm isn't defined on anything but the positive reals. Usually, this extension is called the complex logarithm function, and hence the slightly different symbol 'Log' used above. more here: http://en.wikipedia.org/wiki/Complex_logarithm Edited September 14, 2012 by Bignose 1
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