sl235 Posted October 3, 2012 Share Posted October 3, 2012 Would the 2 items displayed in the image below act as I expect in a zero G environment? Would they retreat away from one as depicted (assuming contact at 45 degrees) Assuming that item A had a mass of 100kg and was stationary, Items B have a mass of 1kg and travel at 10m/s. what formula would I need to use to calculate the velocities and vectors of the items after a collision? Link to comment Share on other sites More sharing options...
swansont Posted October 3, 2012 Share Posted October 3, 2012 You would use conservation of momentum, and, if the collisions are elastic, conservation of kinetic energy. Link to comment Share on other sites More sharing options...
sl235 Posted October 3, 2012 Author Share Posted October 3, 2012 So Kinetic energy of the items just prior to collision would be; Item A = 0 Joules Items B = 50 Joules and momentum; Item A = 0 kg-m/s Items B = 10 kg-m/s and momentum After the collision; Item A = 0.19802 kg-m/s Items B = -9.80198 kg-m/s Is that correct? what vectors would the momentum be carried? Link to comment Share on other sites More sharing options...
swansont Posted October 3, 2012 Share Posted October 3, 2012 The momentum of the system is zero, since momentum is a vector. Each ball has a momentum of 10 kg-m/s, but the signs are opposite. So after the collision, the balls moving down and the frame moving up will have equal momentum magnitudes. The balls each have a KE of 50J, so the total is 100J. Link to comment Share on other sites More sharing options...
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