3 gold coin puzzle

[TimeSpaceLightForce]

Chance Puzzle:

 

3 friends found a pot of gold coins. They agreed to play a game of chance.

Each one toss a coin : wise kid, skillful kid, lucky kid consecutively.

The wise kid schemed : if all the faces of the toss are the same then "skillful kid" lose his share

but if only two faces are the same then "lucky kid" lose his share but

if none of the faces are the same then "wise kid & skillful kid" lose their shares.

The skillful kid agreed because he can make a toss of head or tail as he wants it after the first toss of wise kid.

The lucky kid who was first to found the treasure also agreed because he just lucky.

 

Which of them lost a share ?

[EquisDeXD]

The skillful kid lost his share because all the coins are the same on both sides, so it doesn't matter if the skillful kid can control the result.

Edited October 19, 2012 by EquisDeXD

[TimeSpaceLightForce]

 

The wise kid tossed a coin and it landed on a face, enjoying the scheme w/ 8 results favor--wiseness justified Next, the skillful kid tossed a coin successfully to land on the opposite face --skill justified . Last, the lucky kid tossed the coin--luck must also be justified.So,its spins,and flips,and stand balanced on its thickness side.None of the faces are the same. And the lucky kid wins the pot.

 

The above spoiler is the answer :

 

Hi EquisDeXD- thank you for the reply.

That answer is right in that case. BUT the "skillful kid" will not agree if there is no Head/Tail on the coin.. so please try another.

 

Similarly, if the lucky kid chooses a different coin so that none of the faces will be the same, wise kid will not agree if all the coins are not the same.

Edited October 19, 2012 by TimeSpaceLightForce

[EquisDeXD]

How about this?

 

The lucky kid loses. The wise kid is wise and knows the skillful kid can determine the result, and orders it so that he goes first and get's a head or tails, then the lucky kid goes second and get's a heads or tails, and the skillful kid can determine the last result which will be in his favor.

 

If it was heads-heads, skillful would make the last one tails.

 

If it was tails-tails, skillful would make the last one heads.

 

If it was head-tails or tail-heads, skillful could make it either one and make lucky kid lose but not himself.

 

 

Edited October 20, 2012 by EquisDeXD

[TimeSpaceLightForce]

How about this?

 

 

 

Actually there is only 2 sequences

of toss that the lucky kid might lose:

W-S-L : win

S-W-L : win

S-L-W : win

L-S-W : win

L-W-S : ? (violation of luck or skill)

W-L-S : ? (violation of luck or skill)-- your solution.

 

 

Certainly they all wanted to select position on tossing ,

so they have agreed to tose a coin all at the same time

and whoever got a different face..selects position first.

They could repeat if all are same faces. Lucky kid wins of course.

and selects last position.

 

Then between the two ( wise & skillful kid ) the next to select position is

whoever has a different face as lucky kid's tose. They could repeat

if both their toss are same face. Eventually skillful kid wins.

and selects second position.

 

What was left for the wise kid is the scheming.

and it is wise if theres a condition that he can lose.

 

 

 

Thanks Again

Rouie