fundamental particle mass

[Orion1]

Why has a Newtonian model for fundamental particle masses not been considered?

 

Electroweak gravitation model of an electron:

 

Gravitational force is equal to the electroweak nuclear force:

[math]F_g = F_w[/math]

 

Integration via substitution:

[math]\frac{G m_{\beta}^2}{r^2} = \frac{\hbar c \alpha_{w}}{r^2}[/math]

 

Electroweak gravitation strength of interaction:

[math] \alpha_{w} = \frac{G m_{\beta}^2}{\hbar c} = 1.751 \cdot 10^{-45}[/math]

 

[math]\boxed{\alpha_{w} = 1.751 \cdot 10^{-45}}[/math]

 

Electron mass:

[math]\boxed{m_{\beta} = \sqrt{\frac{\hbar c \alpha_{w}}{G}}}[/math]

 

On a fundamental scale, such an interaction could be represented as an interaction between the two gauge bosons that are the carriers of these fundamental forces, the graviton and an electroweak boson. The Standard Model does not predict such an interaction because the graviton is not considered part of the Standard Model.

[swansont]

Why has a Newtonian model for fundamental particle masses not been considered?

 

Electroweak gravitation model of an electron:

 

Gravitational force is equal to the electroweak nuclear force:

[math]F_g = F_w[/math]

What is the evidence that this is true?

[Orion1]

What is the evidence that this is true?

The evidence is theoretical, however, under the Standard Model, at each energy scale where two fundamental forces interact, the result is a particle mass called a boson.

 

Electrostrong gravitation model of a Planck boson:

 

Gravitational force is equal to the strong nuclear force:

[math]F_g = F_s[/math]

 

Integration via substitution:

[math]\frac{G m_{P}^2}{r^2} = \frac{\hbar c \alpha_{s}}{r^2}[/math]

 

Electrostrong gravitation strength of interaction:

[math] \alpha_{s} = \frac{G m_{P}^2}{\hbar c} = 1[/math]

 

[math]\boxed{\alpha_{s} = 1}[/math]

 

Planck boson mass:

[math]\boxed{m_{P} = \sqrt{\frac{\hbar c \alpha_{s}}{G}}}[/math]

 

On a fundamental scale, such an interaction could be represented as an interaction between the two gauge bosons that are the carriers of these fundamental forces, the graviton and a gluon. The Standard Model does not predict such an interaction because the graviton and Planck boson are not considered part of the Standard Model.

 

Reference:

Planck Mass - Wikipedia

Edited October 25, 2012 by Orion1

[swansont]

Gravitational force is equal to the strong nuclear force:

[math]F_g = F_s[/math]

 

Gravitational force is equal to the electroweak nuclear force:

[math]F_g = F_w[/math]

 

By the transitive property, then, the strong interaction and electroweak interaction are equal. Really?

[Orion1]

By the transitive property, then, the strong interaction and electroweak interaction are equal. Really?

Affirmative, at some relative energy level and interaction range.

 

[math]F_w = F_s[/math]

 

[math]\frac{\hbar c \alpha_w}{r^2} = \frac{\hbar c \alpha_s}{r^2}[/math]

 

[math]\boxed{\alpha_w = \alpha_s = 1}[/math]

 

However, this interaction would result in the generation of another boson at GUT scale energy, that is not included in the Standard Model.

 

X boson mass:

[math]m_X = \frac{\Lambda_{\text{GUT}}}{c^2} = 10^{16} \; \frac{\text{GeV}}{c^2}[/math]

 

[math]\boxed{m_X = 10^{16} \; \frac{\text{GeV}}{c^2}}[/math]

Reference:

Grand Unified Theory - Wikipedia

X and Y bosons - Wikipedia

Edited November 2, 2012 by Orion1

[swansont]

Affirmative, at some relative energy level and interaction range.

What energy would that be?

[Orion1]

What energy would that be?

[math]\Lambda_{\text{GUT}} = 10^{16} \; \text{GeV}[/math]

[Ziven]

I think the formulas that you provided are just for comparing the strong interaction and gravitation interaction in conveniently.

 

You formulas still can't explain why gravitation exists.

 

I think that the weak interaction force you provided is wrong.

The weak interaction is β=gm²c/h_bar.

Where g is fermi constant, m is proton‘s mass.

Edited November 4, 2012 by Ziven

[Orion1]

The weak nuclear force is equal to the Fermi weak nuclear force:

[math]F_w = F_w[/math]

 

Integration via substitution:

[math]\frac{\hbar c \beta}{r^2} = \frac{g E m}{r^2}[/math]

 

[math]E = mc^2[/math]

 

Integration via substitution:

[math]\frac{\hbar c \beta}{r^2} = \frac{g m^2 c^2}{r^2}[/math]

 

Weak nuclear force Fermi mass:

[math]\boxed{m = \frac{1}{c} \sqrt{\frac{\hbar c \beta}{g}}}[/math]

 

Your formulas still can't explain why gravitation exists.

The formulas in previous posts describe gravitation as a field interaction between quantized graviton waves in [math]\hbar c[/math] units, which is the simplest explanation in terms of physics.

 

It would be difficult to explain why electromagnetic waves exist without photons.

Edited November 11, 2012 by Orion1

[Orion1]

If the weak interaction strength equation from post #8 is correct:

[math]\beta = \frac{g m_{\beta}^2 c}{\hbar}[/math]

 

What would the numerical value for [math]\beta[/math] be?

 

Please provide a reference link?

Edited January 31, 2013 by Orion1