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Visible light, I presume, is a photon product. And since photons have no mass or charge, how are they affected by gravity? Black holes don't allow photons to escape, and light is "curved" when passing a large body toward Earth from a distant star, etc. So how can a mass-less unit be affected by gravitational pull?

Posted (edited)

Visible light, I presume, is a photon product. And since photons have no mass or charge, how are they affected by gravity? Black holes don't allow photons to escape, and light is "curved" when passing a large body toward Earth from a distant star, etc. So how can a mass-less unit be affected by gravitational pull?

 

Light still has relative mass, and energy distorts the fabric of space as well. A photon has energy, energy is effected by curvature, and energy is a part of determining the photon's frequency and magnitude.

Edited by EquisDeXD
Posted

Visible light, I presume, is a photon product. And since photons have no mass or charge, how are they affected by gravity? Black holes don't allow photons to escape, and light is "curved" when passing a large body toward Earth from a distant star, etc. So how can a mass-less unit be affected by gravitational pull?

 

Light will always follow the shortest route between points. This is known as the geodesic. Gravity curves the geodesic. Photons always follow the curve of space.

  • 2 weeks later...
Posted (edited)

Visible light, I presume, is a photon product. And since photons have no mass or charge, how are they affected by gravity? Black holes don't allow photons to escape, and light is "curved" when passing a large body toward Earth from a distant star, etc. So how can a mass-less unit be affected by gravitational pull?

The classical explanation of General Relativity is that photons follow the curved lines inward surrounding matter. You also could say that photons, via their momentum/ energy, have a small mass equivalence and thereby react like matter concerning gravity.

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Edited by pantheory

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