Inertia of Meter Stick

[RVJ]

So I'm currently working on some physics homework to prepare for an upcoming exam. We were assigned the following problem:

 

"Calculate the rotational inertia of a meter stick, with mass 0.56kg, about an axis perpendicular to the stick and located at the 20cm mark. (Treat the stick as a thin rod.)"

 

Here is how I attempted to solve the problem:

 

Using the Parallel-Axis Theorem,

I=I_com + Mh²

I found the I_com (using a table of values) to be:

(1/12)ML²

Filling it in for the equation:

I=(1/12)ML² + Mh²

Knowing the values of every variable, I plugged in:

I=(1/12)(.56kg)(1)² + (.56)(.3)²

 

My final answer was:

I=.097 kg-m²

But using the list of answers our Professor provided, it's supposed to be .97 kg-m². I'm inclined to think the professor made a typo?