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Posted (edited)

basic algebra:

 

if a=b
and c=d
then ac = bd eq:I
or ad = bc eq:II
as da = cb
also a + c = b + d eq:III
or a + d = b + c

 

using the above derive the anagrammatist equation from below :

1. t = o n
2. e = o w
3. l = w t
4 . e2 = n v
5. e3 = v l

 

 

 


1&2: (ow)t = e(on) from eq.II ....eq.6

3&4: (nv)l = e2(wt) from eq.II ....eq. 7

7&5: e3(nv)l = (vl)e2(wt) from eq.I ....eq. 8

6&8: e3(nv)l + (ow)t = (vl)e2(wt) + e(on) from eq.III ...eq. 9

expanding the square & cube then omitting parenthesis:
we have : eeenvl + owt = vleewt + eon ...eq.10

 

rearranging: eleven + two = twelve + one

 

 

Edited by TimeSpaceLightForce

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