Jump to content

Kp for H20g+C(s)<=>H2(g)+CO(g)


Recommended Posts

Posted

at 1000K the equilibrium constant for

H20(g)+C(s)<=>H2(g)+CO(g)

is 3.72atm. If total pressure is 25atm what would the partial pressures be?

 

Could someone tell me if i've got the right answer in: 69% reacted.

therefore Partial pressures (Pg): Pg(H20)=3.875 Pg(H2)=8.625 Pg(CO)=8.625

 

i used x=reacted H20 1-x ; C 1 ; H2 x; CO x;

total=3

Xg= 1-x/2; unity; x/2; x/2; for the compounds respectively.

i'm not sure how to treat carbon as it is solid. do i count it as 1 when calculating the equilibrium total moles?

 

thanks in advance.

my Alevel is in a week n i'm not sure of this one

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.