Iota Posted February 16, 2013 Posted February 16, 2013 (edited) I'm trying to determine the (theoretical) end-point for a titration of paracetamol with KOH. So I need to work out the volume of 0.1M KOH required to neutralise 125mg of paracetamol. Information about the practical this is based on: This 125mg of paracetamol tablet is crushed and dissolved in 100cm3, then 25cm3 of this solution is pipetted into a beaker. Titrate this with 0.1M KOH and find the end point. I have a method of doing this but I'm not sure it's correct: 0.125g/ 151.09gmol-1 = 8.27*10-4 mol paracetamol in 100cm3 solution. 8.27*10-4 mol/ 4 = 2.07*10-4 mol paracetamol in 25cm3 solution (the 25cm3 pipetted into a beaker). We are told that the conc. of KOH is 0.1M. With the information available here I said: 0.1M/1000*(x) = 2.07*10-4 mol I rearranged the above to find 'x', which is the volume of solution required to make the same amount of moles that there are of paracetamol, hence enough to neutralise it: (1000*(2.07*10-4))/0.1 = x = 2.7cm3 of KOH required. Is this remotely correct? If not can someone help me out? Thanks in advance. Edited February 16, 2013 by Iota
hypervalent_iodine Posted February 16, 2013 Posted February 16, 2013 I didn't check your math, but the way you've done it looks fine to me.
Iota Posted February 16, 2013 Author Posted February 16, 2013 I've double checked the maths then checked it again, should be all right! Thanks.
Biofanatic24 Posted February 26, 2013 Posted February 26, 2013 Just went over this problem, and yes everything seems to be correct.
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