kingjewel1 Posted December 31, 2004 Posted December 31, 2004 how do i work out that if a machine is worth $15000 and if it's price decreases by 20% per annum that it will cost $9600 in two years using Sn=a(r^n-1)/r-1? using this formula it doesn't work.... thanks guys
5614 Posted December 31, 2004 Posted December 31, 2004 $15000 * 0.8^2 0.8 is a loss of 20% as a decimal... squared (^2) because its for two years.
JaKiri Posted December 31, 2004 Posted December 31, 2004 how do i work out that if a machine is worth $15000 and if it's price decreases by 20% per annum that it will cost $9600 in two years using Sn=a(r^n-1)/r-1? using this formula it doesn't work.... thanks guys That formula is for the SUM of a geometric series, not to find any individual term. Using the same notation (a as initial value, r as ratio and n as number of terms), the equation to find the term is ar^n.
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