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Posted (edited)

I have a question about calculating limits with absolute values. I don't want the solution.



Say for example

 

limitabs.jpg

 

 

 

sign of x2 - 1



___x|_-∞_____-1__+__1______________+∞

x2 -1|_____+___0__-__ 0________+________







sign of x2 + 2x - 3



_______x |_-∞_______-3____ 1_______+∞

x2 + 2x -3 |_____+_____0__-__0___+___



Now my question is how you handle absolutes



for example

 

limcase1.jpg

 

 

in this case:

|x2 - 1| = x2 - 1 or -(x2 - 1) [explain why]

|x2 + 2x - 3| = x2 + 2x - 3 or -(x2 + 2x - 3) [explain why]

 

 

 

limcase2.jpg

 

 

in this case:



|x2 - 1| = x2 - 1 or -(x2 - 1) [explain why]

|x2 + 2x - 3| = x2 + 2x - 3 or -(x2 + 2x - 3) [explain why]

 

 



Thanks in advance.

 

EDIT: It's lim

x->1

Edited by BAndrew
Posted

Well my first comment was that upon initial inspection (and quick check) that neither the top expression nor the bottom ever have negative values - so your signs are clear whatever the limit. Once you know your signs it just becomes a job of deciding what happens as you approach 1

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