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Francesco Celani 1, a stalwart LENR
(Low Energy Nuclear Reactions) experimentalist has built a sucessful cold
fusion generator that has been giving out 5-10 watts for over 6 weeks. It
consists of a glass container filled with hydrogen and containing a long thin
nickel-copper wire. He says he had to“pump” it up for 2 days before getting it
started. It seems that Celani’s idea is to compress as many protons as possible
into the nickel-copper lattices. Roughing up the surface of the wire, as Celani
does, helps absorb protons into the lattice more easily. The protons may be
compressed enough that they could gain enough electrostatic energy to make them
as massive as a neutron. The protons would then form a very tight, compressed
structure. The lattice the protons are contained in should keep this condensed
structure in place.


Since the proton now has the mass of the
neutron, the following reaction can take place:


e-+ u -à d + ve (this
turns the proton into a neutron) The reaction is carried out by the weak
interaction through the exchange of a virtual W- intermediate vector
boson.


If a new neutron is formed in this manner, a
small vacuum of electric repulsion is formed and the rest of the proton
structure around it would cave in on it and one of the protons would join it.
The surrounding protons would squeeze this new n-p pair until it responds by
shoving back and producing vibrations in the proton structure which are carried
to the metal lattice and produce heat. In doing this, the n-p pair loses it
excess energy and becomes a deuteron nucleus. There should be no gamma
radiation released in this process. Detection of deuterium in the final state
of Celani’s generator would help verify this.


The power output should be: P = N T (1.2 x 10-12J)
where N = # protons, T = transition rate (probability of reaction occurring/s)
and 1.2 x 10-12 J is the energy released per event. T is found from:


T = 2(pi)[<f/V(0)\i>]2 p(f)
where p(f) is the density of final states and the interaction matrix, V(0), is
found from the Lagrangian density of the electroweak theory of the Standard
Model:


V(0) = v+eLd+Lo~ui
(ie/(sqrt(2)sinOW))W-u eL uL


The left-handed fields are Dirac fermion fields.
I get:


T = 2(pi)(md/(2Ed))(e/(sqrt(2)sinOW))2(1/(2MW))
(me/(2Ee))(mu/(2Eu))(4(pi)/Ev


~ (6.28 x 10-8)/Ev


For Ev~ .511 MeV and N ~ 1020 (reasonable
from Celani’s set-up data) then P = 15Watts compared to Celani’s 10Watts


A possible method to increase power might be to
include a large nucleus (an inert gas most likely) into the hydrogen mix. When
the large nucleus is absorbed in the metal lattices along with the protons, the
higher electrostatic energy would give the protons their necessary mass more
quickly and without being as compressed.



1 pg 97, Steve Featherstone, “Andrea Rossi’s
Black Box”, Popular Science Nov2012, Vol281 No5



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