Jump to content

Recommended Posts

Posted

In this formula:

 

=============================================

The total power radiated by a ground dipole is


e32e958f8f6d57695f3de4deebeb96fd.png

where

f is the frequency

I is the RMS current in the loop

L is the length of the transmission line

c is the speed of light

h is the height above ground of the ionosphere D layer

σ is the ground conductivity

============================================

 

The smaller the factor σ ---> the larger the power.

------> Does it mean reducing conductivity (or increasing resistivity) increases power ? Is that correct ? confused.gif

 

[ From http://en.wikipedia.org/wiki/Ground_antenna ]

 

Posted

The basic laws of currents tell us that the power dissipated by a resistor is [math]P=I^2 R[/math]. Resistivity [math]\rho[/math], which is proportional to resistance, is related to conductivity [math]\sigma[/math] by the equation [math]\rho \sigma =1[/math]. So yes, that equation looks right to me.

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.