Externet Posted March 26, 2013 Posted March 26, 2013 In this formula: ============================================= The total power radiated by a ground dipole is where f is the frequency I is the RMS current in the loop L is the length of the transmission line c is the speed of light h is the height above ground of the ionosphere D layer σ is the ground conductivity ============================================ The smaller the factor σ ---> the larger the power. ------> Does it mean reducing conductivity (or increasing resistivity) increases power ? Is that correct ? [ From http://en.wikipedia.org/wiki/Ground_antenna ]
elfmotat Posted March 26, 2013 Posted March 26, 2013 The basic laws of currents tell us that the power dissipated by a resistor is [math]P=I^2 R[/math]. Resistivity [math]\rho[/math], which is proportional to resistance, is related to conductivity [math]\sigma[/math] by the equation [math]\rho \sigma =1[/math]. So yes, that equation looks right to me.
derek w Posted March 26, 2013 Posted March 26, 2013 A change in conductivity or resistance,changes the output not the input.
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