emeraldgirl08 Posted April 1, 2013 Posted April 1, 2013 Hi all. I am not sure how I would derive this measurement for my lab. My ochem lab is asking for 'a twofold excess of thionyl chloride.' Not sure what this means. Physical constants I have for thionyl chloride are its MW= 119 g/mol and d= 1.64 g/mL. The other reagent I will put into an RBFalong with the thionyl chloride is 0.4g of m-toluic acid. Do I incorporate 0.4g into my calculation for the excess thionyl chloride? Thanks!
elementcollector1 Posted April 1, 2013 Posted April 1, 2013 I would guess, if the ratio of thionyl chloride to m-toluic acid is 1:1, then you instead use 2 thionyl chloride. In short, use twice as much as you should stoichiometrically.
emeraldgirl08 Posted April 5, 2013 Author Posted April 5, 2013 Yes you were right. This was the calculation that I eventually used: 0.4g X 1 mol/137g X 2 mol/1mol X 119g/mol X 1mL/1.64 In short I made the intermediate acid chloride first then made N,N-diethyl-m-toluamide afterwards. I almost forgot to follow up to this post until I began to assemble my lab report this morning. Just wanted to say thanks! Have a good day
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