finding the gravitational pull of a blackhole

[Christian.D walker]

I know this is crazy but is this even possible? Because if we knew exactly how strong the pull is you could possibly find out how to avoid them.

[swansont]

The pull is what you'd expect of anything with that mass and your distance from it. If you replaced the sun with an equal mass but with a small enough radius such that it was a black hole, we wouldn't notice any gravitational difference.

[elfmotat]

The acceleration required to maintain constant "r" value, i.e. the equivalent of the Newtonian "g" value, is given by:

 

[math]a=\frac{GM}{r^2\sqrt{1-2GM/rc^2}}[/math]