Chuquis Posted April 23, 2013 Posted April 23, 2013 I am doing a titration for school between sodium hydroxide and vinegar. I have no idea what the equation might be so I completely guessed. I was wondering if someone could help me by telling if it's right or not the reaction equation is: CH3CO2H + NaOH --> NaCH3 + CO2 + H2O If it is not correct can someone please tell why and how I may be able to improve it? Thanks a lot
hypervalent_iodine Posted April 23, 2013 Posted April 23, 2013 Definitely not. Can you identify what kind of reaction this might be? Are your reactants acids, bases, etc.?
Murka Posted April 23, 2013 Posted April 23, 2013 Vinegar is essentialy diluted Acetic Acid (CH3COOH) which is a weak acid, Sodium Hydroxide is NaOH which is a strong base. The reaction would be CH3COOH + NaOH <-equilibrium-> (CH3COO-) + (Na+) + (H2O) but pay attention that since this is an equilibrium, not all the (H+) and (OH-) will be H2O, (H+) would be neutralized by (OH-) to form H2O but there will be more (H+) formed by the equilibrium reaction etc' etc' essentially you're looking at the simplified reaction for the acid HA <--equlilibrium--> (H+) + (A-)
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