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Forces


coligro

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I think I could solve it at my own.

 

a)

 

FRes=FG9kg-FG6kg-FF= 9,81 N

 

a=FRes/25kg=0.3924 m*s-1

 

b)

FT= 9kg*9.81-9kg*0.3924m*s-1= 85N

 

c)

FT=6kg*9.81-6kg*(-0.3924m*s-1)= 61N

 

 

Have I done everything correct?

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what all the wired symbols,I can't understand.

let's try my way from , right to left I symbolize the tension and the mass as follows

m1 , t1 , m2 , t2 , m3

then follow me since the motion is to the right,

m1g - t1 = m1a .......(1)

t1 - t2 - ff = m2a ........(2)

t2 - m3g = m3g ........ (3)

solve this you will get what you need.

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