Experiment, maths and physicists

[robinpike]

When we do experiments with electric fields, we do this by building up an excess of electrons. This means that such experiments tell us about the electron’s electric field, rather than also the proton’s electric field.

Therefore, when we do experiments with light and electric fields, these experiments are only finding out about how light interacts with an electron's electric field. These experiments show that the light is not affected by the electron's field.

Physicists have concluded that light does not interact with electric fields, whether that field be from an electron or a proton.

But what SHOULD have been concluded: Is that light does not interact with the electron’s electric field - and left the possibility open that light is affected by a proton’s electric field.

But why should any physicist ask: Is the proton’s electric field different to the electron’s electric field?

And then also ask: If so, how is the proton’s electric field different to the electron’s electric field?

I don’t see how any physicist could use experiment and maths to ask those two questions.

[swansont]

 

When we do experiments with electric fields, we do this by building up an excess of electrons. This means that such experiments tell us about the electron’s electric field, rather than also the proton’s electric field.

 

Who is "we"?

 

All electric fields terminate on negative charge, but they start on positive charge.

[robinpike]

Who is "we"?

 

All electric fields terminate on negative charge, but they start on positive charge.

 

How can that be correct? How would that explain how two electrons interact with each other - where would their electric fields originate from?

[swansont]

How can that be correct? How would that explain how two electrons interact with each other - where would their electric fields originate from?

 

Just because a field terminates on negative charges doesn't mean the field doesn't exist anywhere else.

[robinpike]

Who is "we"?

 

All electric fields terminate on negative charge, but they start on positive charge.

 

The "we" as anybody doing an experiment with electric fields?

 

 

When we do experiments with electric fields, we do this by building up an excess of electrons. This means that such experiments tell us about the electron’s electric field, rather than also the proton’s electric field.

Therefore, when we do experiments with light and electric fields, these experiments are only finding out about how light interacts with an electron's electric field. These experiments show that the light is not affected by the electron's field.

Physicists have concluded that light does not interact with electric fields, whether that field be from an electron or a proton.

But what SHOULD have been concluded: Is that light does not interact with the electron’s electric field - and left the possibility open that light is affected by a proton’s electric field.

 

So what are the experiments that the none "we" people have performed, which use protons as the source of the electric field?

[swansont]

The "we" as anybody doing an experiment with electric fields?

 

Are you asking a question or answering mine? If it's an answer, then you are merely re-asserting a claim for which you have provided no evidence.

 

So what are the experiments that the none "we" people have performed, which use protons as the source of the electric field?

 

A standard capacitor hooked up to a battery will have negative charge on one side and positive charge on the other. How do you get positive charge without protons? If that's not enough, take that configuration, open the circuit and then ground the negative side.

[robinpike]

Thanks Swansont. I was trying to think of a line of reasoning that would challenge the current explanation of quantum effects, without the reasoning having to resort to speculation.

 

I wanted to think of an experiment that might show that the proton's electric field has something to it in addition to its positive field, and therefore also different to the electron's negative field.

 

But what I've now realised, is that such an experiment won't demonstrate anything, for there would be no need to separate out the electron's field if the effect was an additional effect. The effect would always be present, with or without the electron. Back to the drawing board...