janaki Posted May 30, 2013 Share Posted May 30, 2013 A body falls freely from a height 'h' . Find the time taken to reach the ground and the velocity which body hits the ground?? Link to comment Share on other sites More sharing options...
EdEarl Posted May 30, 2013 Share Posted May 30, 2013 No need to post twice. Link to comment Share on other sites More sharing options...
pwagen Posted May 30, 2013 Share Posted May 30, 2013 I really hope the whole exercise isn't to come up with a generalized formula, because I don't want to find out I may have done your whole assignment. Also, it's been years since I did any of this, so I'm probably way off. You have height and acceleration (gravity). You could use the formula [latex]d = t_0 + 1/2at^2[/latex], where d would be h and a would be g, and solve for time. Then it's the simple matter of using the value of t in the formula [latex]v = at[/latex]. Link to comment Share on other sites More sharing options...
daniton Posted May 30, 2013 Share Posted May 30, 2013 there are couple of ways to come up with answer.Try conservation of energy.it's a bet easy and quick .if you are familiar with calculus you can begun from the beginning definition of acceleration, velocity , this kind of thing but really what grade are you? Link to comment Share on other sites More sharing options...
janaki Posted May 30, 2013 Author Share Posted May 30, 2013 Thank you for replay.vt2 = v02 + 2ax here, x=h, a=g therefore, vt2= v02+2gh vt =v0 + gt therefore, t = vt + v0/ g substituting vt2 t2 = vt2- v02/ g2 t2 = v0 + 2gh - v02 t2 = 2h / g t = (2h/g)1/2 is it right ?? there are couple of ways to come up with answer.Try conservation of energy.it's a bet easy and quick .if you are familiar with calculus you can begun from the beginning definition of acceleration, velocity , this kind of thingbut really what grade are you? I'm Studying at 8th standard Link to comment Share on other sites More sharing options...
daniton Posted May 30, 2013 Share Posted May 30, 2013 you don't have to go that much. you got Vt = (2gh)^.5 the t = Vt/g eventhough you are right through that whole process. 1 Link to comment Share on other sites More sharing options...
janaki Posted May 7, 2014 Author Share Posted May 7, 2014 okey Link to comment Share on other sites More sharing options...
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