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Posted

Just re-arrange the equation to give x on one side:

 

x(e-g) = y(h+f)

 

(does this answer the question, or am I being silly? I haven't done this for a while)

Posted

is finding aswers for you hw all you ever use this site for?

 

ex- fy= gx + hy

 

ex-gx= Fy + hy

 

ex-gx= (f+h)y

 

(e-g)x=(f+h)y

 

x=(f+h)y/(e-g)

 

there for for every x there is (f+h)y/(e-g)

 

hope that helps :)

Posted
ex-gx= Fy + hy

 

ex-gx= fhy

 

Er, nope. fy + hy does not equal fhy. Post #1 gives the correct factorisation.

Posted

thanks dave i believe your first post was right. Thanks to you also ed84c, your first few steps was right, but i think you are a little off at last few steps.

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