Blue Posted June 27, 2013 Posted June 27, 2013 (edited) How many primary alcohols, which 3.7g releases 560 cm3 H2 in reaction with Na, are there? I tried to find Mr of alcohol, but I can't get the right solution. Edited June 27, 2013 by Blue
hypervalent_iodine Posted June 27, 2013 Posted June 27, 2013 I guess the first question is do you know what the overall reaction is?
Blue Posted June 27, 2013 Author Posted June 27, 2013 Yes, I've just solved it, thank you anyway. But, I need help with another problem: What is the volume of H2 (normal conditions) which gets released when we add 4.6g of elementary Na into 100g of pure ethanol?
hypervalent_iodine Posted June 27, 2013 Posted June 27, 2013 If you got the first question, then this one should be pretty straight forward. What part of it are you struggling with?
Blue Posted June 27, 2013 Author Posted June 27, 2013 I tried to convert everything into moles, but I don't get the right result, I'm a bit confused about the way I should use m(Na) ?
hypervalent_iodine Posted June 27, 2013 Posted June 27, 2013 If you show me your calculations I can tell you where you might have a problem.
Blue Posted June 27, 2013 Author Posted June 27, 2013 2 CH3-CH2-OH + 2 Na = 2 CH3-CH2-ONa + H2 m( C2H5OH) =100g Mr(C2H5OH)=46g/mol n=m/Mr = 100/46=2.17mol 2mol:1mol=2.17:x x=2.17/2=1.08mol H2 but, this is not right, and don't know how to use m(Na) V(H2)= Vm*n=22.4* number of moles of H2 I don't know how to find n(H2)
hypervalent_iodine Posted June 27, 2013 Posted June 27, 2013 Are you familiar with the concept of limiting reagents at all?
Blue Posted June 27, 2013 Author Posted June 27, 2013 Yes, but I didn't have Chemistry classes for a year, so I can't remember many things. Thank you anyway I solved it
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