Bela Posted July 6, 2013 Share Posted July 6, 2013 n x 10th Bohr's orbit contains how many number of waves?? Thanks Link to comment Share on other sites More sharing options...
studiot Posted July 6, 2013 Share Posted July 6, 2013 (edited) Bohr orbits are subject to the equation [math]n\lambda [/math] = [math]2\pi {r_n}[/math] n = 1,2,3,4.... Where rn denotes the radius of the orbit which contains n wavelengths. Bohr's theory only had one quantum number, n So if n = 10 the circumference of the orbit circle contains 10 wavelengths. Does this help? gosh why is latex so difficult on this site? Edited July 6, 2013 by studiot Link to comment Share on other sites More sharing options...
stefen Posted July 7, 2013 Share Posted July 7, 2013 Hi, According to Bohr orbits theory the equation is n(lambda) = 2* pi* r(sub n) n -> any natuaral number r (sub n)-> the radius of the orbit which contains n wavelengths. so the ans is n Reference: http://chemistry.tutorvista.com/inorganic-chemistry/bohr-s-model-of-the-atom.html Link to comment Share on other sites More sharing options...
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